5x^2+20=625

Solution for 5x^2+20=625 equation:

5x^2+20=625

We move all terms to the left:

5x^2+20-(625)=0

We add all the numbers together, and all the variables

5x^2-605=0

a = 5; b = 0; c = -605;
Δ = b2-4ac
Δ = 02-4·5·(-605)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*5}=\frac{-110}{10}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*5}=\frac{110}{10}
=11
$